The sum of twice a number and 5 is at most 3 less than the number

2x + 5 ≤ x - 3

We can treat this like a usual algebraic equation.

Subtract x from both sides.

x + 5 ≤ -3

Subtract 5 from both sides.

x ≤ -8

Thus, x is less than or equal to the quantity -8.

We can test this by plugging in two values into the original inequality: a number greater than -8, and a number less than -8.

2x + 5 ≤ x - 3

We'll use 2 first.

2 * 2 + 5 ≤ 2 - 3

9 ≤ -1 × this is incorrect

Now  we'll use -10

2x + 5 ≤ x - 3

2 * -10 + 5 ≤ -10 - 3

-15 ≤ -13 √ this is correct

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step-by-step explanation:

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