Which rule transforms quadrilateral abcd to quadrilateral a'b'c'd'? a. (x,> (x,-y-4) b. (x,> (x+6,-y) c. (x,> (x+6,y-4) d. (x,> (-x, y-4)

The rule transforms the quadrilateral ABCD to quadrilateral A'B'C'D' is given by

D.(-x,y-4).

Step-by-step explanation:

Given quadrilateral ABCD  transform into new quadrilateral A'B'C'D.

The transformation is a  special rule by which to determine the coordintae of  image point of any coordinate of given point . The transformation can be rotation, reflection, dialtion etc.

In given figure of qudrilateral ABCD

Coordinate of A (-5,4)

Coordinate of B(0,1)

Coordinate of C (-4,0)

Coordinate of D (-6,2)

In II figure  of quadrilateral A'B'C'D

Coordinate of A' (5,0)

Coordinate of B' (0,-3)

Coordinate of C' (4,-4)

Coordinate of D' (6,-2)

Then we can see that coordinate of A (-5,4) change into A' (5,0)

It means x change into -x and y change into y-4

Similarly in same  way  B (0,1) change into B'(0,-3)

C(-4,0) change into C'(4,-4)  and D( -6,2) change into D'(6,-2)

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

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