Solve for p(x) p(x)=(x^2+x+2)-[2x^2+2(-2x-4)]

This question can be solved through trial and error method looking at the closest possibilities.

p(x)= (x^2 + x+2)- ( 2x^2 +2(-2x -4))

= (x^2 + x+2) - (2x^2 -4x -8)   ( simplify inner brackets)

if x+2=0, x=(-2) ; p(x)= (-2)

( (-2)^2 + (-2)+2 ) - (2X(-2)^2 - 4X(-2) - 8)   ( solve brackets using BODMAS rule)

(4+0) - (2X2 + 8-8)

4-4

= 0

therefore x= (-2)

i would say c is the best answer, hope it's right!

good luck! =)

cutie~

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.