Find the equation of the line in slope-intercept form. through (−5, 6) with slope = 3

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

The slope-point form: y - y₁ = m(x - x₁)

We have:

m = 3 and the point (-5, 6) → x₁ = -5 and y₁ = 6

Substitute:

y - 6 = 3(x - (-5))

y - 6 = 3(x + 5)     |use distributive property

y - 6 = 3x + 15    |add 6 to both sides

y = 3x + 21

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