Graph the line using a point and a slope. write the equation of each line. a line that contains point (0, −3) and perpendicular to another line whose slope is 2.

The line passes through (0, -3)

Its perpendicular to another line whose slope is 2

The slope of the line therefore is -1/2 = -0.5 (the product of slopes two perpendicular lines is -1)

Taking another point (x,y) on the line;

Slope = change in y-axis ÷ change in x-axis

-0.5 = (y - -3) / (x - 0)

y = -0.5x - 3

y=-0.5x-3

Hope this helps!

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this