Point j is on line segment \overline{ik} ik . given jk=2x-1,jk=2x−1, ik=3x+2,ik=3x+2, and ij=3x-5,ij=3x−5, determine the numerical length of \overline{jk}. jk .

Using line segments concepts, it is found that the numerical length of segment jk is of 7 units.

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The measures are:

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Replacing the measures into the equation, we can find x.

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The numerical length of segment jk is:

7 units.

A similar problem is given at link

IJ = 3x - 5

JK = 2x - 1

IK = 3x + 2

   IJ   +    JK   =    IK           segment addition postulate

3x - 5 + 2x - 1 = 3x + 2       substitution

            5x - 6 = 3x + 2       simplify (add like terms)

            2x - 6 = 2             subtraction property (subtracted 3x from both sides)

                  2x = 8             addition property (added 6 to both sides)

                    x = 4             division property (divided both sides by 2)

JK = 2x - 1   = 2(4) - 1   = 8 - 1   = 7

JK = 7

1gm = 1000mg so 0.1gm = 1000mg

first, convert the weight to kg

160lb * 1kg/2.2lb = 72.7kg

next, the dose

72.7kg * 100mg/kg = 7270mg

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)