Genet multiplied a 3-digit number by 1002 and got ab007c, where a, b, and c stand for digits. what was genet's original 3-digit number? genet multiplied a 3-digit number by 1002 and got ab007c, where a, b, and c stand for digits. what was genet's original 3-digit number?

Solution

Here we have to multiply  abc by 1002.

Then we have to positions the digits. We can able to position the digits by comparing the other digits.

In ones place, we have c

In the tens we have 7. in ab007c

By comparing the digits, we get

c = 9

b = 3

a = 5

Therefore, the 3-digit number is 539.

The answer is 539.

Here the resultant a, b, c stands for any digits.

one that is bigger than 3 1/2

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.