Solve using the limit definition, limit as h approaches 0: f(x)=x^3-3x+7 *i know the answer is f'(x)=3x^2-3, but i don't know how to get it using the limit

limit formula is:

f(x + h)= (x + h)³ - 3(x + h) + 7

          = x³ + 3x²h + 3xh² + h³ - 3x - 3h + 7

f(x) = x³ - 3x + 7

f(x + h) - f(x)= (a³ + 3a²h + 3ah² + h³ - 3a - 3h + 7) - (a³ - 3a + 7)

                   = 3x²h + 3xh² + h³  - 3h

= =  3x² + 3xh + h² - 3

as h approaches 0:  3x² + 3x(0) + (0)² - 3   = 3x² - 3

366

step-by-step explanation:

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step-by-step explanation: