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Mathematics, 08.07.2019 11:00 s945924

Given g(x)=-3x-3g(x)=βˆ’3xβˆ’3, solve for xx when g(x)=0g(x)=0.

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Given g(x)=-3x-3g(x)=βˆ’3xβˆ’3, solve for xx when g(x)=0g(x)=0....
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