What is the radius r of the turn if θ = 20.0 ∘ (assuming the car continues in uniform circular motion around the turn)? express your answer in meters?

The answer is 54.18 meters.

Explanation:

Fk = -mg + N cos (20) = 0

Fr = N sin (20)  ( frictional force)

Fr = m (a)         where as a = v²÷r

By putting in the values..

N = mg÷ cos (20)

r = v²÷ g tan (20) (radius equation)

= 13.89²÷ 9.81(tan 20) (gravitational force = 9.81 m/s²)

r = 54.18 meters.

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