The angular velocity of a point on a circle with a diameter of 24 feet is 15π radians per second. find the approximate speed of the point on the circle. 2.5 ft/sec 3.9 ft/sec 565 ft/sec 1,131 ft/sec

Given

angular velocity of a point on a circle is 15π radians per second

diameter of circle 24 feet

Find the approximate speed of the point on the circle

To proof

Radius of circle = 12 feet

angular velocity of a point on a circle =  15π radians per second

FORMULA

where V  = Linear velocity

          r = radius of the circle

put values in the above equation

we get

V = 12× 15п  

( π = 3.14)

put this in the above equation

we get

V = 12 × 15 × 3.14

 = 565.2 feet per second

Thus approximate speed of the point on the circle  565 feet per second

Hence proved

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

answer: b f g .

step-by-step explanation: