Mr. schwartz builds toy cars. he begins the week with a supply of 85 wheels, and uses 4 wheels for each car he builds. mr. schwartz plans to order more wheels once he has fewer than 40 wheels left. the inequality that can be used to find the number of cars, x, mr. schwartz builds before he places an order for more wheels is − x < 40. mr. schwartz will need to order more wheels after building cars.

solution: Mr. Schwartz will need to order more wheels after building 12 cars.

explanation:

Mr. Schwartz begins with total number of wheels = 85

he has to order more wheels once he left with less than 40 wheels

so min. no. of wheels he can use before ordering more wheels = 85-40 = 45

Mr. Schwartz uses 4 wheels to build 1 car

Mr. Schwartz uses 45 wheels to build 45÷4 = 11.25 cars

then, if he builds 12 cars then he needs 12×4 = 48 wheels

total supply of wheels he begins with = 85

wheels he used to build 12 cars = 48

so total number of wheels remaining  are = 85-48 = 37

since 37 is less than 40 so after building 12 cars Mr. Schwartz need to order more wheels.

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

they used 313 gallons of paint