The perimeter of two similar triangles abc and pqr are 25cm and 15cm respectively. if one side of the first triangle is 9cm. find the corresponding side of another triangle

The answer is:    " 5  cm "  ;  

or, write as:         " 5. 4 cm " .

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25/15 = 9 /x  ;

Reduce the "25/15 " :

→  " (25/15)  =  (25÷5) / (15÷5)  =  "(5/3)" ;

→  And rewrite:  

→  5 / 3  =  9 / x  ;

Cross-multiply:

→  5 x  = 3 * 9  ;

→  5x   =  27  ;

Divide each side of the equation by "5" ;   as follows:

→  5x / 5  = 27 / 5 ;

to get ;

→   x =  27 / 5 ;

       =   {27 ÷ 5} ;

→  x  =  " 5  cm "  ;  

or, write as:  " 5. 4 cm " .

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this doesn't make sense lol