Find the area of each shape by decomposing each shape into rectangle and/or triangle. for #1, i got 52, is this correct? for #2, i got 120, is this correct?

Remark

You don't have to decompose the second one, and it is better if you don't. Just find the area as you probably did: use the formula for a trapezoid. You have to assume that the 6cm line hits the 2 bases at right angles for each of them, otherwise, you don't know the height. So I'm going to assume that we are in agreement about the second one.

Problem One

The answer for this one has to be broken down and unfortunately, you answer is not right for the total area, although you might get 52 for the triangle. Let's check that out.

Triangle

Area = 1/2 * b * h

base = 16 cm

h = 10 - 4 = 6

Area = 1/2 * 16 * 6

Area = 48

Area of the Rectangle

Area = L * W

L = 16

W = 4

Area = L * W

Area = 16 * 4

Area = 64

Total Area

Area = 64 + 48

Area = 112  of both figures <<<< Answer

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl