Find values of a and b that make the statement |a+b|= |a|+|b| false.

The values that make this statement falser are any in which a and b do not have the same sign.

For instance, if a was equal to 3 and b was equal to -3 than see the results.

|a+b|=

|3+-3|=

|0|= 0

Then see the next equation with the same selections

|a|+|b|

|3|+|-3|

3 + 3 = 6

And this would be true no matter which is the negative, as long as there is one negative and one positive.

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

figure c

step-by-step explanation:

hope this .