Find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (-4, -3) lies on its terminal side

The negative coordinates -4 and -3 tell us that the terminal side of this angle theta lies in Quadrant III.  The hypotenuse is   sqrt( [-4]^2 + [-5]^2 ), or +5.

Then:

sin theta = opp / hyp = -3/5

cos theta = adj / hyp  = -4/5

tan theta = opp / adj = (-3) / (-4) = 3/4

cot theta = adj / opp = 4/3

sec theta = hyp / adj = -5/4

csc theta = hyp / opp = -5/3

answer: you need the equation in the question so i can answer it

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