Find three consecutive even integers. such that 4 times of first integer is 18 more than the sum of second and third integers

integers:  

x

x + 2

x + 4

4x - (x + 4) = 2 (x + 2) + 6

3x - 4 = 2x + 4 + 6

3x - 4 = 2x + 10

x = 14

integers:  14, 16, 18

check  4 (14) - 18 = 2 (16) + 6

                                  38 = 38

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2