Ab and cd bisect each other at e. ce = x 2 â 3, ae = 6x â 10 and cd = 66. find ab.

ae = eb = 6x - 10   segment bisector theorem

ce = ed = x² - 3     segment bisector theorem

ce + ed = cd         segment addition postulate

x² - 3 + x² - 3 = 66   substitution

2x² - 6 = 66             simplify (added like terms)

2x² = 72                  addition property of equality

 x² = 36                  division property of equality

 x  = 6                   square root property of equality

ae + eb = ab         segment addition postulate

6x - 10 + 6x - 10 = ab   substitution

12x - 20 = ab                simplify (added like terms)

12(6) - 20 = ab             substitution

72 - 20 = ab                simplify

52 = ab                       simplify

ab = 52

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine