In the figure, `deltaabc` is congruent to `deltaadc`. if the square abcd is dilated by a factor of 2 to form a'b'c'd', what is the ratio of the area of a'b'c'd' to the area of abcd? 2: 1 3: 1 4: 1 5: 1

The square is dilated by a factor of 2 to form A'B'C'D'.

Which mean the new square sides will be twice as much as the old square.

Let the side length of the square ABCD = x

∴ The side length of the square A'B'C'D' =2x

∵ The area of the square = (side length)²

Area of ABCD = x²

Area of A'B'C'D'= (2x)² = 4x²

∴ Area of A'B'C'D' :  Area of ABCD = 4x² : x² = 4 : 1

hey there!

12 is twice as much as 6 because 6 goes into 12 2 times.

since the rabbit is twice as tall, we should multiply the weight of the first rabbit, 0.25, by 2.

0.25 x 2 = 0.5

therefore, the 12 inch chocolate rabbit weighs 0.5 lb, or half a pound.

hope this !

4444444444444 i think