At the per fair, darlene's dog weighed 5 times as much as leah's dog. together, the dogs weighed 84 pounds. how much did each dog weigh? complete the bar model. write an equation and solve

A) Dd + Ld = 84

B) Dd = 5*Ld      

B) -Dd +5 * Ld = 0  Then adding A) and B)

6 * Ld = 84

Leah's Dog = 14 pounds

Darlene's Dog = 84 -14 = 70 pounds

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

s

step-by-step explanation: