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![\bf x^3=\cfrac{1}{8}\implies \sqrt[3]{x^3}=\sqrt[3]{\cfrac{1}{8}}\implies x=\sqrt[3]{\cfrac{1}{8}}\implies x=\cfrac{\sqrt[3]{1}}{\sqrt[3]{8}} \\\\\\ x=\cfrac{\sqrt[3]{1^3}}{\sqrt[3]{2^3}}\implies x=\cfrac{1}{2}](/tpl/images/0068/9918/ecaaf.png)
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Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4...
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