Agroup of winning ticket holders share equally 90,000,000 lottery. before the money is divided, three more winning ticket holders are declared. as a result, each persons share is reduced to 5,000,000. how many people were in the original group of winners

Let's assume

people were in the original group of winners as x

A group of winning ticket holders share equally 90,000,000 lottery

Before the money is divided, three more winning ticket holders are declared

so, total number of winning tickes =x+3

each persons share is reduced to 5,000,000

so, total money =5,000,000*(x+3)

and this must be equal to total money

now, we can solve for x

and we get

Subtrac both sides by 3

so,

number of people were in the original group of winners is 15 ...........Answer

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: