Find the larget of the three consecutive integers such as 3 times the sum of the first and third integer is equal to 30 more than 4 times the second integer

first integer: x

second integer: x + 1

third integer: x + 2

3[(x) + (x + 2)] = 4(x + 1) + 30

3(2x + 2) = 4(x + 1) + 30

6x + 6 = 4x + 4 + 30

6x + 6 = 4x + 34

2x + 6 = 34

2x = 28

x = 14

14, 15, 16

how is that middle school

step-by-step explanation:

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it