Refer to ohm's law given in the previous question. if the voltage in a circuit is 35+j12 volts and the resistance is 2+j4 ohms, what is the current? a) −596+j293 amps b) −196+j293 amps c) 33−j8 amps d) 5910−j295 amps e) 37+j16 amps f) 118−j164 amps

Ohm's Law:  voltage = resistance times current.  Here we know voltage and resistance, but must calculate the current.

current = voltage / resistance

                            35 + 12j

Here, current = amps

                           2(1+2j)

We must rationalize the denominator (remove 'j' from the denom.).  To do this, multiply numerator and denominator of the above fraction by (1-2j), obtaining:

(25+12j)(1-2j)       25-50j+12j+24        49 - 36j

= = ohms (answer)

2(1 + 4)                         10                       10

answer: the first graph

step-by-step explanation:

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.