What is the point slope form of an equation for the line that has the indicated slope and contains the given point slope= 1.3; (-6.1,5.3)

The point-slope form of the equation of the line is:

Given:

slope of the line = 1.3

point of the line =

The equation of a line represented in point-slope form can be expressed as:

Where,

Substitute the values into the point-slope equation

The point-slope form of the equation of the line that contains a slope value of 1.3 and a point (-6.1, 5.3) is

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y - 5.3 = 1.3 (I x + 6.1 )

the equation of a line in ' point- slope form ' is

y - b = m (x - a) → m is the slope and ( a , b ) a point on the line

here m = 1.3 and ( a , b ) = ( - 6.1 , 5.3 )

y - 5.3 = 1.3 ( x -( - 6.1)) ⇒ y - 5.3 = 1.3 ( x + 6.1 )

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: