Find the distance between the point and the plane. (round your answer to three decimal places.) (1, 2, 1) x − y + 2z = 2

Answer : Distance of plane from a given point =0.408

Explanation:

Since the equation of plane is x-y+2z-2=0

and the given point is (1,2,1)

And we know the formula of distance of plane from a point

i.e.

D=

where A,B,C are the coefficient of x, y, z respectively ,

and are the given points .

So,

=

=

=

Now by using calculator we can find the value of √6 i.e. 2.449 upto three decimal places.

∴ Distance = 0.408

do you have a picture of the table

it is 10.6 according to my calculations