Mathematics, 09.07.2019 19:30 HopeBordelon4
What is the directrix and focus of the parabola 6y-x^2=0
Answers: 1
![\bf \textit{parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 ~\hspace{7em} \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 6y-x^2=0\implies 6y=x^2\implies 6(y-0)=(x-0)^2 \\\\\\ 4 \stackrel{p}{\left(\frac{3}{2}\right)}(y-\stackrel{k}{0})=(x-\stackrel{h}{0})^2](/tpl/images/0070/5215/823fd.png)
, and then we move DOWN "p" units to get the directrix at  
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