The sum of three consecutive integers is 312

Let x be for unknown number. Let x be first number . X+1 To be second number .x+2be third number.  X+(x+1)+(x+2)=312. Simplify to get 3x+3=312 . Subtract 3 from both sides 3x-3=312-3. Once you subtract get 3x=109.then divide 3 both sides . 3x/3=309/3. To get x= 103.   Now once you have that  First number 103. Second number 103+1=104 . And third number 103+2=105.    To check add them 103+104+105=312

a: inscribed angles

step-by-step explanation:

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