How do you find x and y from this diagram? i have no

50 + (3x - y) = x + (2x - 16). Combine like terms to change the 2nd part to get 3x - 16. 50 + 3x-y = 3x - 16. Subtract 3x from both sides to get 50 - y = -16. Subtract 50 from both sides to get -y = - 66, or y = 66. 90 - 50 = 40 = 3x - 66. Add 66 to both sides to get 3x = 106, or x = 35 1/3.

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.