Aprospective mother and a prospective father are hemophiliacs. (enter your answers as fractions.) (a) find the probability that their child would be a hemophiliac male. (b) find the probability that their child would be a hemophiliac female. (c) find the probability that their child would be a carrier. (d) find the probability that their child would be symptom-free.

So remember that Hemophilia is a recessive, x linked trait.

For a woman to have hemophilia, she must have the trait linked to both x chromosomes. For a man to have hemophilia, he must have the trait linked to his singular x chromosome.

For this, I will be making a Punnett Square to determine the Possibilities:

Since there is a 1/2 chance for their offspring to be a boy, and of that 1/2 both would be hemophiliacs, there is a 1/2 chance for the child to be a hemophiliac male.

As previously mentioned, for a woman to have hemophilia, they would need to have that trait attached to both x chromosomes. Since there is a 1/2 chance for their offspring to be a girl, and of that 1/2 both would be hemophiliacs (since they both carry the trait on both chromosomes), there is a 1/2 chance that they will have a hemophiliac female.

So a carrier is someone who carries a recessive trait, but it isn't displayed due to the dominant trait masking it. With x-linked traits, only women can be carriers since they carry more than one x chromosome. What this asks is the probability of an offspring having the trait attached to only 1 of the x chromosomes. Looking at the girls, since both carry the traits on both x chromosomes, there is 0 chance of a carrier.

So symptom free is as it seems, without the hemophilia trait. Looking at the table, since all the offspring contain the hemophilia trait, there is 0 chance that any of their offspring will go symptom free.

for the first question it would be the second answer for the second question it would be the third answer and for the third question it would be the first answer

step-by-step explanation:

good luck!

cutie~