Given: △afd, m∠f=90° df=7√3 , m∠d=30° find: area of △afd

We need to find the area of a triangle whose one side and two angles are given.

The area of is .

In

From the trigonometric identities we have

Area of a triangle is given by

The area of is .

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Using the definition of the tangent function, you can find ...

... FA = DF·tan(30°) = (7√3)·(1/√3) = 7

Then the usual formula for triangle area can be used:

... Area = (1/2)bh = (1/2)·(7√3)(7)

... Area = (49/2)√3 square units

... ≈ 42.44 square units

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

um is there supposed to be a picture?