What is the nth term of -4,-3,0,5,12,21,32?

The first set of differences is   1,3,5,7,9,11

second set of difference = 2 so this is a quadratic sequence  with first term n^2

subtract n^2 from the sequence:-

-4  -  3    0     5

1      4     9    16

-5   -7    -9     -11  

This last series is an AP with nth term = - 5-2(n - 1)

so nth term  for original series is n^2 - 5 - 2(n - 1)

= n^2  - 2n  - 3  answer

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

step-by-step explanation: