Arectangular parking lot has a perimeter of 820 ft. the area of the parking lot measures 42,000 ft2. what is the width of the parking lot?

A rectangle, let length=a and width=b

perimeter: a+a+b+b=820

2a+2b=820  --> a+b = 410

Make a or b the subject: a=410-b

Area: ab=42 000 (area of a rectangle, length x width)

Sub a in.

b(410-b) = 42000

Expand: 410b - b^2 = 42000

Rearrange and use quadratic formula: b^2 -410b + 42000=0

b= 210 (can only be positive because length cannot be negative)

Sub this value back into perimeter or area equation: a + 210 = 410 --> a =200

Therefore, a= 200 and b=210.

Depending what you made the width is, it should be 200ft.

(I may have made some calculation errors as i'm not used to typing it out, but the process should be correct) I hope helps! :)

The answer is C. 210

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.