Find an equation of the circle that satisfies the given conditions. center at the origin; passes through (1,6)

x² + y² = 37

The equation of a circle centred at the origin is.

x² + y² = r² ( where r is the radius)

The radius can be calculated using the distance formula

r = √(x₂ - x₁ )² + (y₂ - y₁)²

where (x₁ , y₁) =(0,0) and (x₂ ,y₂) = (1 ,6)

r = √(1 - 0)² +(6 -0)² = √1 + 36 =√37⇒ r² = (√37)² = 37

x² + y² = 37  is the equation of the circle

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w