Evaluate the integral. (sec2(t) i + t(t2 + 1)3 j + t2 ln(t) k) dt

We have been given a vector valued function:

In order to evaluate the integral of this vector valued function, we will integrate each component of the vector valued function.

Upon integrating each of the components, we get:

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

true

step-by-step explanation: