F1 = (7.4,4.0) and f2 = (-7.4,-6.2) where all components are in newtons. what is the exact x-component of f1 + f2 (in newtons)?

We are given : f1 = (7.4, 4.0)  and f2 = (-7.4, -6.2).

Where each first coordinate is x-component and second coordinate is y-component of force in newtons.

So, for f1, we have x-component = 7.4 newtons and y-component = 4.0 and

for f2, we have x-component = -7.4 newtons and y-component = -6.2.

In order to find exact x-component of f1 + f2, we just need to add those x-component of f1 + f2.

On adding

x-component of f1 + x-component f2, we get

7.4 +(-7.4) = 7.4 -7.4 = 0.

So, final answer is the exact x-component of f1 + f2 is 0 newton.

yor answer is 7/6 times 5

step-by-step explanation: