The length of a rectangle is 4 more than 3 times the width. if the perimeter of the rectangle is 56, what is the length of the rectangle

The relation between the width and the length is : l = 3w +4 -- eqn (1)  Perimeter = 56  » 2w + 2l = 56  Dividing through by 2 gives;  w + l = 28  w = 28 - l  -- eqn(2)  Substitute eqn (2) in eqn (1)  » l = 3(28-l) +4 Expanding bracket gives;  l = 84 - 3l +4 Grouping like terms , we have;  l + 3l = 84+4  4l = 88 l = 88/4  l = 22 The length of the rectangle is 22 units.

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316