If two people are randomly chosen from a group of eight women and six men, what is the probability that (a) both are women; (b) both are men; (c) one is a man and the other a woman?

a) Choice 1: 8 women out of 14 total, Choice 2: 7 women out of 13 remaining

x = =  ≈ 30.8%

b) Choice 1: 6 men out of 14 total, Choice 2: 5 men out of 13 remaining

x = =  ≈ 16.5%

c) Choice 1: 8 women out of 14 total, Choice 2: 6 men out of 13 remaining

x = =  ≈ 26.4%

idk

step-by-step explanation:

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x