Atrain travels from city a to city b and then to city c. the distance from a to b is 120 miles and the distance from b to c is 187.5 miles. the average speed from a to b was 40 miles per hour, and the average speed from b to c was 75 mph. what was the average speed from a to c (that is for the entire trip) in miles per hour?

The distance from a to b is d1=120 miles, distance from b to c d2=187.5 miles

average speed (velocity) from a to b is v1=40 miles/hour

average speed from b to c is v2=75 miles/hour

The formula for average speed from a to c is v= (d1+d2)/(t1+t2)

We have not time and we will calculate it

t1=d1/v1= 120/40=3 hour   and t2=d2/v2=187.5/75=2.5hour

Average speed for a to c is

v=(120+187.5)/(3+2.5)= 307.5/5.5= 55.9 ≈ 60miles/hour

Good luck!!!

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?