The second of three numbers is 3 times the first number. the third number is 5 more than the second number. if the second number is decreased by twice the third the result is 5 find the three numbers.

b=3a

c=b+5

b-2c=5

b-2(b+5)=5

b-2b-10=5

-b=15

b=-15

c=-15+5

c=-10

-15=3a

a=-5

The numbers are -5, -15, and -10

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(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

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