Twice a number increased by 3 is less than the number decreased by 4

Set it up like this: 2n+3 < n-4

Solve for n:

2n+3 < n-4

-n        -n                (1st step: get n on one side by itself)

n+3 < -4

  -3   -3                (2nd step: subtract 3 from both sides)

n < -7

The answer is n < -7

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x