Brass is made from a mixture of copper and other elements. a mixture that is 80% copper is combined with a mixture that is 60% copper, resulting in 100 pounds of brass that is 65% copper. which equation can be used to find x, the amount of 60% mixture used to create the 65% mixture?
a. 0.8(100 – x) + 0.6x = 100(0.65)
b. 0.6(100 – x) + 0.8x = 100(0.65)
c. 0.8(100) + 0.6x = 0.65(100 - x)
d. 0.6(x) + 0.8(100 + x) = 0.65

a.0.8(100 – x) + 0.6x = 100(0.65)

Step-by-step explanation:

The easiest way to find the answer is to derive the equation from the the data given.

The amount of 60% mixture is given as .

The amount of copper from 60% mixture =

The amount of copper from 80% mixture =

Therefore total amount of copper in 100 pound mixture is:

The amount of copper from 60% mixture + The amount of copper from 80% mixture

⇒

We can rearrange the equation as:

Percentage of copper in the final mixture can be derived by:

[Total pounds of copper/Total pounds of the mixture]×100

Percentage of copper in the final mixture is given as 65%

Therefore,

[Total pounds of copper/Total pounds of the mixture]×100=65%

=

This equation can be used to find the value of ..

Therefore the answer is a.0.8(100 – x) + 0.6x = 100(0.65)

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7