Answer questions 1 and 2 as best you can. 1. if h(x)=(fog)(x) and h(x)=3sqrt7x+1, find f(x) and g(x) 2. if n(x)=(fogoh)(x) and n(x)=(sqrt2x)^5, find f(x), g(x), and h(x)

Hey, Are you in K12/TXVA too? We might be in the same class and could help each other out. Either way, here's the

f(x) = x^5

g(x) = sqrt(x)

h(x) = 2x

You place h(x) in g(x) and then that inside of f(x).

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

49%

step-by-step explanation:

when you realize that you dont know just realize i just took a test and im so smart