Triangle abc is translated on the coordinate plane below to create triangle a'b'c': triangle abc, triangle a prime b prime c prime, and parallelogram efgh on the coordinate plane with ordered pairs at a negative if parallelogram efgh is translated according to the same rule that translated triangle abc, what is the ordered pair of point h'? (4 points) (−3, −3) (4, 9) (7, 6) (0, −5)

Your answer is (1, -7) What u do: label out the triangles points: A(-7, 6), B(-5, 3), C(-1, 3) to A'(1, 4), B'(3, 1), C'(7, 1)A to A' which is -7 to 1 is a 8 point difference and A to A' which is 6 to 4 is a -2 point difference, indicating: (x + 8, y - 2) B(-5, 3) -> (-5 + 8, 3 - 2) = B'(3, 1) C(-1, 3) -> (-1 + 8, 3 - 2) = C'(7, 1)Now to simply solve for H to H': We know H 's coordinates are: (-7, -5) Now add in the rule and solve: Now add in the rule and solve: (-7 + 8, -5 - 2) = 1,-7 Hope this helps :)

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

d

step-by-step explanation: