Dvd cases are sold in packages of 20. padded mailing envelopes are sold in packets of 12. what is the least number of cases and envelopes you could buy so that there is one case for each envelope with none left over?

3 packages of DVD cases and 5 packets of padded mailing envelopes.

Step-by-step explanation:

Hi, to answer this question we have to find the Least Common Multiple (LCM) of 20 (DVD cases) and 12 (envelopes).  

20: 20,40,60,80  

12: 24,36,48,60  

Since DVD cases are sold in packages of 20: to find the number of packages we have to divide the number of DVD cases that we could buy (60) by the number of DVD cases that each package contains (20).

60/20 = 3 packages of DVD cases  

And for the envelopes (12)  

60/12 =5 packets of Padded mailing envelopes  

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a