Correct answer only ! what are the solutions to the equation? x2 (4x − 3) (5x − 1) = 0

Condition One

x^2 = 0

sqrt(x^2) = sqrt(0)

x = 0

Condition Two

4x - 3 = 0

4x = 3

x = 3/4

Condition 3

5x - 1 = 0

5x = 1

x = 1/5 or

x = 0.2

A graph certainly helps with this problem. The places where this function crosses the x axis are the places which are the answers to your question. They are marked with a small dot.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐