Find the lesser of the two consecutive integers with a sum greater than 16

Let n be an integer number, the next integer number is n+1. These numbers n and n+1 are two consecutive integers.

Their sum is n+n+1=2n+1 and is greater than 16, thus

2n+1>16.

Solve this inequality:

2n>16-1,

2n>15,

n>7.5.

Since n is integer, then the smallest integer that sutisfies this inequality is 8 and the next n+1=8+1=9.

the lesser of two consecutive integers is 8.

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.