Find the equation of the line tangent to the function at the given point f(x)=5x^2 at x=10

f(x) = 5x²

f(10) = 5(10)²  = 5(100)  = 500

f'(x) = 10x

f'(10) = 10(10)   = 100  

Now, find the line that passes through (10, 500) and has a slope of 100

y - y₁ = m(x - x₁)

y - 500 = 100(x - 10)

y - 500 = 100x - 1000

        y = 100x - 500

step-by-step explanation:

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this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

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about the problem:

srry i'm not done ! i'll

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: