An equation is shown below: 5(2x – 3) = 5 part a: how many solutions does this equation have? (4 points) part b: what are the solutions to this equation? show your work. (6 points)

Remark

Sometimes you can avoid the distributive property. This is one of those cases. Start by dividing by 5. You can only do this is there a common factor between the left and right sides of the equal sign.

Solve

There is only 1 solution. If there was an x^2 somewhere, you would have 2 and if there was an x^3 there would be 3.

5(2x - 3) = 5           Divide both sides by 5

5(2x - 3)/5 = 5/5

(2x - 3) = 1              Remove the brackets.

2x - 3 = 1                Add 3 to both sides.

2x = 1 + 3

2x = 4                    Divide by 2

x = 4/2

x = 2  <<<<< Answer

Part A:

It has One Solution

Part B:

Step 1: 5(2x - 3) = 5

Step 2: (5 x 2x) - (5 x 3) = 5

Step 3: 10x - 15 = 5

Step 4: 10x - (15 + 15) = 5 + 15

Step 5: 10x - 0 = 20

Step 6: 10x = 20

Step 7: (10x ÷ 10) = (20 ÷ 10)

Step 8: x = 20/10

Step 9: x = 20/10 = 2

Step 10: x = 2

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation: