Aball is thrown downward from the top of a building with an initial speed of 25 m/s. it strikes the ground after 2.0 s. how high is the building, assuming negligible air resistance

Use one of the equations of motion under constant acceleration:-

s = ut + 0.5at^2   where s = distance, u - initial velocity, a = acceleration ( in this case it is gravity = 9.81 m s^-2)  and t = time.

here we have s = 25*2 + 0.5*9.81 * 2^2

= 69.62 meters answer

square root

step-by-step explanation:

the answer is c)8

step-by-step explanaction: